Total no. of possible outcomes = 12 {1, 2, 3,…., 12}

**(i) Let E ⟶ event of pointing 10**

No. favourable outcomes = 1 {10}

P(E) = (No.of favorable outcomes)/(Total no.of possible outcomes) = 1/12

**(ii) Let E ⟶ event of pointing at an odd no.**

No. favourable outcomes = 6 {1, 3, 5, 7, 9, 11}

P(E) = 6/12 = 1/2

**(iii) Let E ⟶ event of pointing at a no. multiple of 3**

No. favourable outcomes = 4 {3, 6, 9, 12}

P(E) = 4/12 = 1/3

**(iv) Let E ⟶ event of pointing at an even no.**

No. favourable outcomes = 6 {2, 4, 6, 8, 10, 12}

P(E) = 6/12 = 1/2